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4x+12-21=x^2+3x
We move all terms to the left:
4x+12-21-(x^2+3x)=0
We add all the numbers together, and all the variables
4x-(x^2+3x)-9=0
We get rid of parentheses
-x^2+4x-3x-9=0
We add all the numbers together, and all the variables
-1x^2+x-9=0
a = -1; b = 1; c = -9;
Δ = b2-4ac
Δ = 12-4·(-1)·(-9)
Δ = -35
Delta is less than zero, so there is no solution for the equation
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